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is my answer is right miss Divya.... please conform me.....
If y = Asin(wt - kx) , where y & x are displacement , A is amplitude & t is time . then what are the dimensions of w & k.
hi mam. I wanted to get some preparation question for nstse exam. can u help me?
y = sin^(-1)(w t-k x) k = 0, t = 0, y = 0 Reduce[y == ArcSin[t w - k x], {k, t, w, x, y}, Integers] w = (k x sin(y))/t{value of W} Re(y) = pi/2 Re(y) = -pi/2 (d)/(dx)(sin^(-1)(w t-k x)) = -k/sqrt(1-(t w-k x)^2)
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