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Angel Agarwal
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there r some basic information about physics........... [ Download ]

11 Mar, 2013 5:06 PM

two people played 5 matches in chess.But each one of them won equal number of matches.How is that possible?

06 Nov, 2011 12:20 AM

Ans: dravid had 24 & sachin had 12 marbles. ----the last statement of your question is "after the 3rd game, each boy had exactly the number of marbles he had started with, and dravid had twice as many marbles as sachin". ----that means even at the start...ie. before playing the 1st game, dravid had twice as many marbles as sachin. ----now lets say that sachin had "X" marbles at start of the game. that means dravid had "2X" marbles at the start of the game.
----now after 1st game, dravid gave half of his marbles to sachin.
----that is after 1st game, dravid had X marbles and sachin had 2X marbles.
----now after 2nd game, sachin lost 3/4th of his marbles to dravid.
----that means after 2nd game, the number of marbles dravid had =
= X + 3/4 (2X)
= X + 3/2 X
= 5/2 X.
----but it is given that, dravid had 30 marbles after the 2nd game.
----therefore,
5/2 X = 30
X = 12.
----thus, at the start, sachin had 12 marbles and dravid had 24 marbles.
CROSSCHECK :-
.................................................................sachin................dravid
original amount of marbles....12...................24
after 1st game(dravid lost half ie 12)......24.......................12
after 2nd game (sachin lost 3/4th ie 18)........6..................30
after 3rd game (sachin won some ie 6)..........12..................24

05 Aug, 2010 8:30 PM

Ans: dravid had 24 & sachin had 12 marbles. ----the last statement of your question is "after the 3rd game, each boy had exactly the number of marbles he had started with, and dravid had twice as many marbles as sachin".
----that means even at the start...ie. before playing the 1st game, dravid had twice as many marbles as sachin.
----now lets say that sachin had "X" marbles at start of the game. that means dravid had "2X" marbles at the start of the game.
----now after 1st game, dravid gave half of his marbles to sachin.
----that is after 1st game, dravid had X marbles and sachin had 2X marbles.
----now after 2nd game, sachin lost 3/4th of his marbles to dravid.
----that means after 2nd game, the number of marbles dravid had =
= X + 3/4 (2X)
= X + 3/2 X
= 5/2 X.
----but it is given that, dravid had 30 marbles after the 2nd game.
----therefore,
5/2 X = 30
X = 12.
----thus, at the start, sachin had 12 marbles and dravid had 24 marbles.
CROSSCHECK :-
.................................................................sachin......................................dravid
original amount of marbles..........................12............................................24
after 1st game (dravid lost half ie 12)..........24............................................12
after 2nd game (sachin lost 3/4th ie 18)........6..............................................30
after 3rd game (sachin won some ie 6)..........12............................................24

05 Aug, 2010 8:23 PM

after a long time i posted a Q...........

FIND THE NUMBER OF MARBALS

"Dravid and Sachin each had a certain number of playing marbles. Dravid lost a game to Sachin and had to give Sachin half of his marbles. In the second game, Sachin lost and had to give three-fourths of his marbles to Dravid, who now had thirty marbles. Finally, the two played a third game. Sachin won and acquired some of Dravid?s marbles.At this point, each boy had exactly the number of marbles he had started with, and Dravid had twice as many marbles as Sachin. How many marbles did Sachin has in the beginning?"

09 Sep, 2009 4:23 AM

**partnership share**

**P,Q & R start a business by INVESTING Rs.40000, 50000 & 90000 respectively. P is given 10% of the profit as salary & the rest is divided amongest them in the ratio of their contributions. P's partnership share is...........**

18 Jul, 2009 8:39 AM

First J---->B , John& brother crosses in 3 mts J<---- John came back in 1 mt F----->G , Father & Grandpa crosses in 12 mt B <----Brother came back in 3 mts J----->M , John & mother crosses in 6 mts J <----John came back in 1 mt J---->B, lastly John & bother crosses in 3 mts.
So total of 29 mts. So they cross the river in 29 mts. |

08 Jul, 2009 12:41 PM

"John and his family members want to cross to the other side of the bridge at night. They have only one lamp which lasts for only 30 minutes. A maximum of only two persons can cross at one time, and they must have the lamp with them.Each person walks at a different speed. John walks at a speed of 1 min, his brother jack walks at 3 min, his mother Julie walks at 6 min, his father Jeff walks at 8 min and his grandpa George walks at 12 min.A pair must walk together at the rate of the slower person.How can JohnÂ’s family cross the bridge?"

07 Jul, 2009 8:38 AM

I'm not confident , but i think it is 12:10 hrs............

am i right............

05 Jul, 2009 11:23 AM

**Interview Time**

The MD entered the conference room 10 minutes before 12.30 hrs for interviewing. He came 20 minutes before the chairman who was 30 minutes late. At what time the interviews scheduled?

30 Jun, 2009 3:27 AM