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Discussion

Reasoning Preparation for Civil Services - CSAT
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A leap year contains 366 days. each day repeated 52 times with a balance of 2days .The two days may be one of the following.{(mon tue) (tue, wed), (wed, thur),(thur.fri), (fri, sat), (sat,sun), (sun, mon)} 7 possibilities n(s) =7 if the year has 53 Mondays, 53 Tuesdays are possible only then the last two days (mon, tue)favourable case=1 Required probability =1/7 (choice D)

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