Call Support +91-85588-96644
TCYonline

Login

Sign Up

Please enter a Username or Email ID
Please enter a password
Keep me logged in
Please enter your name
Please enter your mobile number
You can't leave Captcha Code empty
By submitting this form, you agree to the Terms & Privacy Policy.
OR

Sign Up via Facebook

Sign Up via Google

Sign Up via Twitter

Download Software
Tests given

Download TCY App

App Image

The heat of reaction for C10H8 (s) + 12O2 (g) 10 CO2 (g) + 4H2O () at constant volume is -1228.2 kcal at 25 oC. The heat of reaction at constant pressure and the same temperature is

 
-1228.2 kcal
-1229.4 kcal
-1232.9 kcal
-1242.6 kcal

Reply


Please type your answer before submitting.
Submit

C10H8 (s) 12O2 (g) 10 CO2 (g) 4H2O () We know, = Heat at constant pressure = Heat at constant volume = -1228.2 x 103 cal = Change in gaseous moles = 10 - 12 = -2 T = 298 K and R = 2 cal = -1228.2 x 103 (-2)(2)(298) = -1229392 cal = -1229.392 kcal