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A heavy nucleus at rest breaks into two fragments, which fly off with velocities in the ratio of 8 : 1. The respective ratio of the radii of the fragments (assumed spherical) is

 
1 : 2
1 : 4
4 : 1
2 : 1

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As the particles have different velocities their masses are different. Considering this as a SUPER ELASTIC COLLISON we get. m1v1=m2v2, as,v1:v2=8:1 ;hence m1:m2=1:8, also nuclear density is constant, let it be=D,let the volume of the particles be v1 and v2 respectively. now, v1:v2=m1/D:m2/D=1:8, as volume of a sphere=4/3 pie Rcube, R1cube:R2cube=1:8; hence,R1:R2=1:2

Solution mistake .