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In a town of 10,000 families, it was found that 40% families buy newspaper A, 20% families buy newspaper B and 10% families buy newspaper C. 5% families buy A and B, 3% buy B and C, 4% buy A and C. What is the number of families which buy none of A, B and C, if 1% of the families buy all the three newspapers?

 
3,300
3,500
4,000
4,100
5,000

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Correct answer is 4100 not 4300