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Probability of success is S = 1/4
probability of failure is Q= 3/4
from binomial theorem with n=2 r=0 we have
ncr(P)^r(Q)^(n-r)=
2c0(1/4)^0(3/4)^2 = 9/16 ans
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Probability of success is S = 1/4 probability of failure is Q= 3/4 from binomial theorem with n=2 r=0 we have ncr(P)^r(Q)^(n-r)= 2c0(1/4)^0(3/4)^2 = 9/16 ans