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How can 12ac – b2 – 2bc + 6ab be factorised?

 
(12ac – b2) b (2c – 6a)
(6a + b) (2c – b)
(6c + b) (2a – b)
(2c + b) (6a – b)

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How can 12ac – b2 – 2bc 6ab be factorised?Write your comments on whether the question is tricky / difficult / wrong.