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Quantitative Aptitude Preparation for CA - CPT

Posted on Aug 09, 2016 9:50 AM

Given log2 0 3010 and log3 0 4771 then the value of log6 is

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Log2*log3=log6=log2+log3

0.3010+.4771= .7781

.7781

1.......press 6 on calculator n2.........19 times root bottonn3........ -1n4.........x227695n