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If f(x) = (loge x2), then f'(x) at x = e is equal to

 
(1 - loge 2)
(1 + loge 2)
(-1 + loge 2)
(1 + loge 2)
(loge 2)

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Wrong 👎 question its should be x power3 not x base 3 in the question