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Question :
Every day a cyclist meets a train at a particular crossing. The road is straight before the crossing and both are travelling in the same direction. The cyclist travels with a speed of 10 km/h. One day the cyclist comes late by 25 mins and meets the train 5 km before the crossing. What is the speed of the train?
Right Answer Explanation:
When the cyclist is 25 mins late, he met the train 5 km ahead of crossing. He can cover these 5km in 5/10 = ½ hour = 30 mins. To travel these 5 km, cyclist takes 30 mins.
But he is already late by 25 mins, so in the next 5 mins, the train will cover 5km. Therefor, the train ‘s speed = 60 km/h
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Question : Every day a cyclist meets a train at a particular crossing. The road is straight before the crossing and both are travelling in the same direction. The cyclist travels with a speed of 10 km/h. One day the cyclist comes late by 25 mins and meets the train 5 km before the crossing. What is the speed of the train? Right Answer Explanation: When the cyclist is 25 mins late, he met the train 5 km ahead of crossing. He can cover these 5km in 5/10 = ½ hour = 30 mins. To travel these 5 km, cyclist takes 30 mins. But he is already late by 25 mins, so in the next 5 mins, the train will cover 5km. Therefor, the train ‘s speed = 60 km/h