A motorcycle moving with a velocity of 72 km/hour on a flat road takes a turn on the road at a point where the radius of curvature of the road is 20 m. The acceleration due to gravity is 10 m/s². In order to avoid skidding, he must not bend with respect to the vertical plane by an angle greater than

Θ = tan⁻¹ (2)

Θ = tan⁻¹ (6)

Θ = tan⁻¹ (4)

Θ = tan⁻¹ (25.92)

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Nike

OPTION 1 IS THE RIGHT ANSWER

Reply (2) (0)

Arinjoy

We know ,
tanɵ = v^2/(r*g) < where v= velocity of motorcycle, r= radius of the curvature & g= acceleration due to gravity>
tanɵ= 20^2/(20*10)
tanɵ=2
ɵ=tan−1 (2)
so OPTION 1 IS CORRECT.

Reply(1) (0) (0)

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