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In a class of 100 students, 39 play tennis, 58 play cricket, 32 play hockey, 10 play cricket and hockey, 11 play hockey and tennis, and 13 play tennis and cricket. The number of students who play all three games is

 
4
5
6
7

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5 is correct use formula P(AuBuC)=p(A) p(B) p(C)-p(A^B)-p(B^C)-p(B^C) p(A^B^C)

Solve it : 100=39 58 32-10-11-13 (T^C^H)

B