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Let ABCD be a parallelogram whose diagonals intersect at P and let O be the origin, then " equals

 
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2"
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4"

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Answer is (D) 4 OP since P which is the intersection of diagonals of parellogram it bisects the diagonal so OP = (OA+OC)/2 or OA + OC = 2*OP.............................................1 similarly OB +OD =2*OP.................................2 adding 1 and 2 OA + OB + OC + OD = 4 OP