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Let ABCD be a parallelogram whose diagonals intersect at P and let O be the origin, then 
" equals
Answer is (D) 4 OP since P which is the intersection of diagonals of parellogram it bisects the diagonal so OP = (OA+OC)/2 or OA + OC = 2*OP.............................................1 similarly OB +OD =2*OP.................................2 adding 1 and 2 OA + OB + OC + OD = 4 OP
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j + 
k are linearly dependent vectors and |c| =
, then
, 
and 
are non-coplanar unit vectors such that 
(
, then the angle between 
satisfies the equation 
and 't' is a scalar entity, then 
acting along lA, lB and lC, respectively, in equilibrium, where l is the incentre of ABC. Then, 
is
Options given are wrong ... i think this is the 7-8th time i m finding misprints in your options..everytime error is there in either the questions or the answers....when will u wake up tcy ..u neither reply to your students comments. hate you