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Vishal chugh asks : Find the remainder when 1*2+2*3+3*4+....+99*100 is divided by 101 
Category : Quantitative Ability |  On : 2011-11-28 09:47:11
 
Natarajan says :
30/11/2011 01:59:53
ans is ===0 (remainder) solution: i am software programmer i create a code to find 1*2+2*3+........99*100=333300/101=3300 remainder==0; the program is: package coma; public class frac { public static void main(String args[]){ int a=1,sum=0; for(int i=0;i
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Manish asks : Q. Find the remainder when 34! is divided by 73. 
Category : Quantitative Ability |  On : 2011-04-20 05:05:09
 
Manish says :
23/04/2011 12:38:02
Hii Bharat.. can you please explain the solution
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Nandini ohri asks : The length of a field is 50m.If the field is divided into half and be multiplied by78.25+62.75.What will be the length of the road around the field.haha 
Category : Grade 8 |  On : 2010-11-09 12:41:48
 
Mayank modi says :
11/11/2010 01:15:46
r u a physco
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Nandini ohri asks : The length of a field is 50m.If the field is divided into half and be multiplied by78.25+62.75.What will be the length of the road around the field.haha 
Category : Himachal Pradesh Board |  On : 2010-11-09 12:40:43
 
10/11/2010 07:19:23
50x0.5=25(78.25 62.75) = 25(141) = 3525
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Saurabh singh asks : f(x) = ax2 + bx + c. If f(x) is exactly divisible by x + 1 and x + 2 but leaves a remainder of 12 when divided by x – 1, find the value of c. 1. 3 2. 4 3. 5 4. 2 
Category : Quantitative Ability |  On : 2010-10-14 11:08:22
 
14/10/2010 03:37:15
the correct ans is 4 dear
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