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Karthik says :
Subject :
ho
24/12/2011 13:07:42   |  Reply
Subject : time and distance
a person travels from his house to his office at 5km/h and reaches 20 min late.if his speed had been 7.5 km/h, he would have reach 12 min early.find distance from his house to office??????
14/01/2010 23:41:52   |  Reply
suryadevara mounika says : 20/01/2010 09:00:42
consider time as xhrs.he reached 20min(1/3hr) late so x (1/3). so take 1st equation as 5=d/(x (1/3)).similarly next time he is 12min(1/5hrs) early so 2nd equation is7.5=(d/x-(1/5)).solve and find x value and substitute x value in any equation and ul get distance.
suryadevara mounika says : 20/01/2010 09:01:27
inform me if im wrong
anusha h says : 25/07/2010 16:56:36
8km