As the Germans have to save at least 30% of the bridge, they can destroy at most 70% of it. Also, as 2 missiles have to hit the target, these conditions will be only obtained in the following 2 cases:
rnCase 1: Missiles 1 and 2 hit but 3 and 4 dont
rnThe probability of this happening is 1/3 x 2/3 x 1/4 x 1/5 = 1/90
rnCase 2: Missiles 1 and 4 hit their mark and 2 and 3 dont
rnThe probability of this happening is 1/3 x 1/3 x 1/4 x 4/5 = 1/45
rnThus, the total probability = 1/90 + 1/45 = 1/30
rnHence, answer option 4 is correct.
(0.4)*(0.4)*(0.4)*(0.4)