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If 2x2 +
When lambda=0, then centre is(2,-3). therefore , it's radius is 3root(2).
The equation of the curve through the point (1, 0) and slope 
is:
In queston it is give that dy/dx=(y-1)/(x^2-x)but correct question is dy/dx=(y-1)/(x^2 x)
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