Answer is : 0 a^2+b^2+C^2 = ab + bc+ca a^3+b^3+c^3 = (a+b+c)(a^2+b^2+C^2-ab-bc-ca) = (a+b+c)(ab+bc+ca-ab-bc-ca) { as a^2+b^2+C^2 = ab + bc+ca } = (a+b+c)(0) Thus, answer is 0..... Hope It Works...!!!!

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(a2=a*a b2=b*b c2=c*c)