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Find the HCF of 111...11 hundred ones and 11..11 sixty ones. Plz solve this question with explanation.

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111...11 hundred ones = (111...20 ones) X k similarly 111...60 ones = (111...20 ones) X k' So HCF = 111...20 ones (It is directly the HCF of 60 & 100 = 20 ones)