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Let's say the no is x, divisor is p
First condition
x= np + 23
2nd Condition
2x=mp + 11
Mulitply (1) by 2 and subtract
(m-2n)p= 35
P is integer and m-2n is integer and also p>23
Considering all conditions, we get p= 35
Note: If you double the number, remainder should be doubled ( if 2 times of remainder is more than divisor)..ie. (2 x 23=46), but given is 11.
So divisor is less than 46 and difference ( 2x23-11) should be divisible by Divisor.
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Let's say the no is x, divisor is p First condition x= np + 23 2nd Condition 2x=mp + 11 Mulitply (1) by 2 and subtract (m-2n)p= 35 P is integer and m-2n is integer and also p>23 Considering all conditions, we get p= 35 Note: If you double the number, remainder should be doubled ( if 2 times of remainder is more than divisor)..ie. (2 x 23=46), but given is 11. So divisor is less than 46 and difference ( 2x23-11) should be divisible by Divisor.