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In a circle of radius 17cm,two parallel chords are drawn on opposite side of a diameter.The distance between the chords is 23cm.If the length of one chord is 16cm,then the length of the other is:- (a) 34 cm (b) 15 cm (c) 23 cm (d) 30 cm

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Length of other is also 30cm. in this circle,consider one half in which d length of chord is given 16cm, here a right tr. is formed wid hypot=rad=17cm, base=8cm(perp from d centre bisects d chord). let d perp=x cm. by pythagor. thm, (17sqr)=8 sqr+x sqr this implies x=15cm the distance btw d chords is 23cm this implies d other part is 23-x cm= 8cm in the other half circle, see the rt trangle, wid perp=8cm,hypot=17cm, apply the pythagoras thm 2 get the base =15cm again apply the result that perp from the centre bisects the chord . this implies length of chord=2(15)=30cm.