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I think you meant that they were connected in series to a 250 Volt supply. Supply is not normally rated in Watts.
OK, now let us proceed.
250 V, 200 watts means that the current is 0.8 amps (let us use DC now so that we don\'t have to deal with power factors and RMS / Peak voltages etc.). So, the resistance will be 250 / 0.8 = 312.5 ohms.
Remember, V X I = power and V / I = Resistance where V is voltage and I is the current.
Now the second bulb is rated as 250 v and 100 watts so current will be 0.4 amps and the resistance will be 250 / 0.4 = 625 ohms.
When both the bulbs are connected in series, the total resistance will be the sum of the two resistances, 625 + 312.5 = 937.5 ohms and the current drawn will be
250 / 937.5 = 0.267 amps and the power in the circuit will be 250 X 250 / 937 .5 = 66.67 watts
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I think you meant that they were connected in series to a 250 Volt supply. Supply is not normally rated in Watts. OK, now let us proceed. 250 V, 200 watts means that the current is 0.8 amps (let us use DC now so that we don\'t have to deal with power factors and RMS / Peak voltages etc.). So, the resistance will be 250 / 0.8 = 312.5 ohms. Remember, V X I = power and V / I = Resistance where V is voltage and I is the current. Now the second bulb is rated as 250 v and 100 watts so current will be 0.4 amps and the resistance will be 250 / 0.4 = 625 ohms. When both the bulbs are connected in series, the total resistance will be the sum of the two resistances, 625 + 312.5 = 937.5 ohms and the current drawn will be 250 / 937.5 = 0.267 amps and the power in the circuit will be 250 X 250 / 937 .5 = 66.67 watts